You have
N
bulbs in a row numbered from
1
to
N
. Initially, all the bulbs are turned off. We turn on exactly one bulb everyday until all bulbs are on after
N
days.
You are given an array
bulbs
of length
N
where
bulbs[i] = x
means that on the
(i+1)th
day, we will turn on the bulb at position
x
where
i
is
0-indexed
and
x
is
1-indexed.
Given an integer
K
, find out the
minimum day number
such that there exists two
turned on
bulbs that have
exactly
K
bulbs between them that are
all turned off
.
If there isn't such day, return
-1
.
Example 1:
Input: bulbs: [1,3,2] K: 1 Output: 2 Explanation: On the first day: bulbs[0] = 1, first bulb is turned on: [1,0,0] On the second day: bulbs[1] = 3, third bulb is turned on: [1,0,1] On the third day: bulbs[2] = 2, second bulb is turned on: [1,1,1] We return 2 because on the second day, there were two on bulbs with one off bulb between them.
Example 2:
Input: bulbs: [1,2,3] K: 1 Output: -1
Note:
1 <= N <= 20000
1 <= bulbs[i] <= N
bulbs
is a permutation of numbers from
1
to
N
.
0 <= K <= 20000